Start by calculating the base current as you did but using the right resistor value, unless of course you intended to use a different value for that resistor.
Multiply by the Beta to get the collector current Ic, which is directed downward.
Use Thevenin and/or Norton to convert the battery and 20k to a current source in parallel with the 20k, we'll call it Ix.
The current through the two now parallel resistors is Ip=Ix+Ic, and remember Ic will be negative or simply subtracted from Ip as: Ip=Ix-Ic.
Multiply Ip times the parallel resistance of the 20k and 200k to obtain Vo.
Check to see that the solution voltage is actually possible with a 10v battery.
View attachment 101214
Using KVL as
-1 + (30K Ohm)(IB)+0.7=0
Base Current is found to be IB= 800uA,
I am confused how to find Vo and Io , please describe mathematically.
Nice diagram by Bordodynov in post #3. That illustrates the electrotopological transformation to simplify the problem nicely i think. Unfortunately it looks like the OP may not be returning or is taking a long time to reply.