An amplifier has a decibel power gain of 32dB. What is the ordinary power gain?

Now if dB= 10 log P out / P in

How do I rewrite thew formula to find the ANSWER of 1584.89???

 

Originally posted by tjjam2003@Apr 18 2006, 07:31 PM
An amplifier has a decibel power gain of 32dB. What is the ordinary power gain?

Now if dB= 10 log P out / P in

How do I rewrite thew formula to find the ANSWER of 1584.89???

[post=16293]Quoted post[/post]​

10 * log P out / P in =32
So log P out / P in = 3.2

Get antilog of 3.2. On my calculator that's
Shift > Log > 3.2 = 1584.893192

 

On the off chance that you might not know what an antilog is. It is the same as raising 10, the base of common logarithms, to the power of the argument. In symbols:

antilog(3.2) = 10 ^ 3.2

If you already knew this, then I apologize for being presumptuous.

 

Thank you very much...BIG HELP !!

Originally posted by Papabravo@Apr 18 2006, 08:11 PM
On the off chance that you might not know what an antilog is. It is the same raising 10, the base of common logarithms, to the power of the argument. In symbols:

antilog(3.2) = 10 ^ 3.2

If you already knew this, then I apologize for being presumptuous.

[post=16299]Quoted post[/post]​

 

Originally posted by pebe@Apr 19 2006, 05:57 AM
10 * log P out / P in =32
So log P out / P in = 3.2

Get antilog of 3.2. On my calculator that's
Shift > Log > 3.2 = 1584.893192

[post=16294]Quoted post[/post]​

thanks

on my casio fx-100 c calculator

to get antilog of 3.2

302>shift>log?1584.893