A newbie here so pardon my understanding of electronics.

I have a question about power factor correction for three phase delta, inductive load. Let me first walk through my math. For a balance load, Phase A, B, C has resistance of 2 ohm and inductance of 5 mH, and let frequency be 100 Hz.

1. I find the inductive reactance, Xl = 2*pi*f*L

2. The impedance in each phase is then, Z = 2 Ohm + j 3.14 Ohm

3. Convert #2 into phasor form to find the angle, Thetha = tan-1(3.14 /2 Ohm) = 57.5 degrees

4. If the phase voltage, Vab = 60 V, 0 degrees, then PF = cos (0 – 57.5) = 0.53

My question is how do I calculate the value of capacitor required to do a power factor correction to have PF of 0.8? From my understanding, because current leads in capacitive loads, this helps compensate the fact that current lags in inductive load. On another web site, I’ve seens a PF correction equation that is C = 1/(2*pi*f*X), Is this formula correct? And if so, is X the inductive reactance?