I repair my owen, in main board have a resistor as picture but I don't know its value, please help me! Behind circuit this resistor is bridge diot

 

Picture look unidentified,its color is red orange black gold black,

 

23 ohms 20%, Or if it's an Inductor 23uH 20%.

 

It does look like a wire wound device, and the color code makes no sense for a resistor.

 

23 ohms 20%, Or if it's an Inductor 23uH 20%.

A 20% component is not going to have 3 digit bands.

Assuming the stated colors (Post #2) are correct, the sequence is either:

red orange black gold black

or

black gold black orange black

Having gold as a digit makes no sense, so that rules out the latter.

The gold could be either multiplier or tolerance. If it's a multiplier, then black is the tolerance. But black is not a standard tolerance band, so it is probably not a multiplier.

That makes it 23 with a multiplier of black (10^0) and 5% tolerance. Provided we can determine what the fifth black band is. More often than note, an additional band beyond the tolerance band is the temperature coefficient and a black band is 250 ppm/K

So, if it's a resistor, it would appear to be

23 Ω, 5%, 250 ppm/K

The problem with this is that 23 is not a preferred E24 value (22 and 24 are).

Are you positive that the second band is orange? Is there any chance that it is either red, yellow, or violet?

I haven't been able to five a chart for a five-band inductor in which the first band isn't silver (usually double-width) to indicate military grade. So while that doesn't rule out the possibility of it being an inductor,

Can you take a better-focused picture, perhaps of the other side?

 

Thank all for your help, I buy a 22 ohm for replace its. And now, my owen had running again. Sorry for my bad English. Thank all!