Hi,
For a project, i'm wanting to use a photodiode and a microcontroller to log ambient light levels in my garden.
I need an op-amp circuit that will output 5v to the microcontroller when ambient light is equivalent to 5mW/cm^2.
The photodiode I have is TEMD6010FX01
Below is what I have for a start

Can anyone advise me on weather this is right, and if so how can I work out what C1 and R1 need to be

Tim

 

Need to know the output current of the photodiode at 5mW/cm^2 illumination.
Do you have a data sheet for it?

 

http://www.vishay.com/docs/81308/temd6010.pdf

 

According to the data sheet the diode has a nominal sensitivity of 1μA per 1mW/cm^2 with a 5V reverse bias.
It does not give the current with zero bias as your circuit shows.
So if you apply a 5V reverse bias to the diode anode than a value of 1megΩ for R1 will give a nominal output of 5V for an illumination of 5 mW/cm^2.

But note that the diode sensitivity tolerance is -25% to +225% so, if you need better accuracy then that, you will need to calibrate the circuit or get a diode with a better sensitivity tolerance.

 

Thanks for the response!
Is this what you mean?

 

That's forward biasing the diode.
It needs to be -5V.