Hi,
I have a problem and I am stuck to one question:
The area of a triangle is given by the formula: A=1/2*b*c*sin(θ )
At time to, we have bo=10 inches, co=20inches, θo=pi/3
a) Find the area of the triangle at to
I found 50*sqrt(3)
b- find the rate of change of the area with respect to b at to.
I found 5*sqrt(3).
c) Find the rate of change of the area with respect with θ at to.
I found 50.
d) Using the rate found in part c) , calculate (by differentials) the approximate change in area if angle theta is increased by one degree.
I need help for this question. I do not know what to do here.
Thank you for your help
I have a problem and I am stuck to one question:
The area of a triangle is given by the formula: A=1/2*b*c*sin(θ )
At time to, we have bo=10 inches, co=20inches, θo=pi/3
a) Find the area of the triangle at to
I found 50*sqrt(3)
b- find the rate of change of the area with respect to b at to.
I found 5*sqrt(3).
c) Find the rate of change of the area with respect with θ at to.
I found 50.
d) Using the rate found in part c) , calculate (by differentials) the approximate change in area if angle theta is increased by one degree.
I need help for this question. I do not know what to do here.
Thank you for your help