You wrote it as Vout/Iin. This cannot be a transfer function because it has units of Ω. The correct left hand side is Vout/Vin, and has been pointed out in the given diagram it is 1. If you include the source resistance, as is usual then you can get the more meaningful expression where the capacitor impedance gets smaller with an increase in frequency. It is quite apparent that you need to go back adn review basic concepts before trying to swim in waters where drowning is a distinct possibility.Hi Papa,
Please can you provide me the correct transfer function if the above function is wrong. And also, please can you do the mathematical calculations to find out cut/corner frequency?.