this trivial question just popped up in my mind ,its not a hw question
if we connect 2 ideal power sources ( 2 batteries for example of same voltage V)
to a common load (a bulb of some power rating) how much current will
flow through the bulb . if we consider that I amp flows if only one battery was
there. if R is resistance of bulb assumed. (I=V/R).also assume conductors to have 0 resistance.
i did not try it on paper but have given some thought to it
-- parallel batteries should share the load and hence equal current should flow
case1- since parallel batteries are connected voltage is equal to one battery
acting alone hence current= V/R=I
so shud I/2 current flow in each loop?
case 2-
since two batteries are connected each provides V/R=I
and current thru bulb equals --2I
case 3-
apply superposition theorem
since voltage sources are ideal while considering each source separately
the removed voltage crkt is shorted hence current through bulb is zero in
both consideration. so is the current thru bulb 0+0=0 amps
please reply..
if we connect 2 ideal power sources ( 2 batteries for example of same voltage V)
to a common load (a bulb of some power rating) how much current will
flow through the bulb . if we consider that I amp flows if only one battery was
there. if R is resistance of bulb assumed. (I=V/R).also assume conductors to have 0 resistance.
i did not try it on paper but have given some thought to it
-- parallel batteries should share the load and hence equal current should flow
case1- since parallel batteries are connected voltage is equal to one battery
acting alone hence current= V/R=I
so shud I/2 current flow in each loop?
case 2-
since two batteries are connected each provides V/R=I
and current thru bulb equals --2I
case 3-
apply superposition theorem
since voltage sources are ideal while considering each source separately
the removed voltage crkt is shorted hence current through bulb is zero in
both consideration. so is the current thru bulb 0+0=0 amps
please reply..