if we connect 2 ideal power sources ( 2 batteries for example of same voltage V)

to a common load (a bulb of some power rating) how much current will

flow through the bulb . if we consider that I amp flows if only one battery was

there. if R is resistance of bulb assumed. (I=V/R).also assume conductors to have 0 resistance.

i did not try it on paper but have given some thought to it

-- parallel batteries should share the load and hence equal current should flow

case1- since parallel batteries are connected voltage is equal to one battery

acting alone hence current= V/R=I

so shud I/2 current flow in each loop?

case 2-

since two batteries are connected each provides V/R=I

and current thru bulb equals --2I

case 3-

apply superposition theorem

since voltage sources are ideal while considering each source separately

the removed voltage crkt is shorted hence current through bulb is zero in

both consideration. so is the current thru bulb 0+0=0 amps

please reply..