It's just showing that the gain keeps rolling off below the gain of 1 point.I don't understand the line going negative from the crossing point. What are they trying to tell me here?
Yes, I did find it curious, but not enough to want to dig into the Op Amps internal circuitry to explain why. I'm afraid that is still a bit of a reach for me. Still need to more work on transistors as yet.just the location of the circuit signal ground and input are interchanged.
The internal op amp circuitry (other than the capacitor that provides the 20dB/decade rolloff) has nothing to do with the change in bandwidth between the inverting and non-inverting configuration.but not enough to want to dig into the Op Amps internal circuitry to explain why
I missed that bit first time through. That is something I had not even considered. I assume that occurs when R1 is greater than R2? Not sure that I can fathom why that would be necessary. Especially considering the low voltages and currents that Op Amps typically deal with. Not only an amplifier but an attenuator as well. Something I should breadboard and think about a bit... Thanks for the heads up!A negative dB is a gain of <1.
Hi Sam.hen kept increasing R2 to attempt to get attenuation below the input.
Remember the Gain equation for a non-inverting amplifier:Set up a standard noninverting OPA circuit with R1=R2.
View attachment 257657
View attachment 257658
EDIT: Then kept increasing R1 to attempt to get attenuation below the input.
View attachment 257659View attachment 257660View attachment 257662View attachment 257663View attachment 257664View attachment 257665
Never achieved attenuation below input! So, is this OPA phase shift protected? Is attenuation not possible? The Bode plots show the plot for negative gain so what am I missing here?
by Duane Benson
by Jeff Child
by Aaron Carman