Do you know any rule that tells you the base to emitter voltage for a BJT in active mode?
By the way, that is an NPN, not a PNP.
Bob
This is an NPN I should've written that correctly I apologize. I don't know how to determine the base to emitter voltage for a BJT in active mode.hi M85,
Welcome to AAC.
Is this Homework or a College assignment.?
E
This isn't being graded for any assignment or anything.hi M85,
Welcome to AAC.
Is this Homework or a College assignment.?
E
So the base emitter voltage would be typically 0.7V like a single PN junction would be. Then the 5.7V at the base because of the Zener diode. So the Vout would be 23.6?hi M85,
Check the datasheet for a typical Silicon transistor.
E
Use the Typical value.
Not even close.So the Vout would be 23.6?
It would have to be 5V there. Right?Can you write the voltage equation for this loop:
View attachment 248779
5V.Not even close.
Hint: The transistor is acting as an emitter follower.
That's the approximate voltage for silicon transistors.So the base emitter voltage would be typically 0.7V like a single PN junction would be.
That's what I get...It would have to be 5V there. Right?
I thought it was AC at first as well. Then it just made zero sense to me at that point.I also thought it said "ac" at first. Then I thought then why have the +/- signs. Closer inspection revealed the "d".
by Jake Hertz
by Jake Hertz
by Jake Hertz
by Jake Hertz