Hi everyone,
I've the following problem:
http://s9.postimg.org/6wgvejisv/Untitled.png
I've assumed that that the node between 4 ohms resistor, 3 ohms resistor and 9 Volts source, and the node between 9 Volts source, 2 ohms resistors and 6 ohms resistor, are forming a Supernode.
So, Applying KCL on the Supernode:
\(I_{4 \Omega}=I_{3 \Omega}+I_{2 \Omega}+I_{6 \Omega}\)
\(\frac{V_{1} - 21}{4}=\frac{V_{1}}{3}+\frac{V_{2}}{2}+\frac{V_{2}}{6}\)
\(V_{1}+8V_{2}=-63 \rightarrow (1)\)
Applying KVL on the Supernode:
\(-V_{1}-9+V_{2}=0\)
\(V_{1}-V_{2}=-9 \rightarrow (2) \)
Solving (1) and (2):
V1= -63, V2=-9
Which - as you can see above - not the right answer.
Any help?
I've the following problem:
http://s9.postimg.org/6wgvejisv/Untitled.png
I've assumed that that the node between 4 ohms resistor, 3 ohms resistor and 9 Volts source, and the node between 9 Volts source, 2 ohms resistors and 6 ohms resistor, are forming a Supernode.
So, Applying KCL on the Supernode:
\(I_{4 \Omega}=I_{3 \Omega}+I_{2 \Omega}+I_{6 \Omega}\)
\(\frac{V_{1} - 21}{4}=\frac{V_{1}}{3}+\frac{V_{2}}{2}+\frac{V_{2}}{6}\)
\(V_{1}+8V_{2}=-63 \rightarrow (1)\)
Applying KVL on the Supernode:
\(-V_{1}-9+V_{2}=0\)
\(V_{1}-V_{2}=-9 \rightarrow (2) \)
Solving (1) and (2):
V1= -63, V2=-9
Which - as you can see above - not the right answer.
Any help?