I need help dropping current though a water solenoid valve. I have a dauquiri machine that needs water running through it when the compressor is on. Rather than have to turn on/off water manually, I added a 110v water inlet valve that gets power only when the compressor is on. The valve is a generic one for refrigerators that has 2 spade plugs and a 110v coil. Perfect for my use. My problem is with direct 110v AC the 188ohm solenoid gets super hot after a few minutes. I shut it down at 250 degrees. I now realize the refrigerators must have a regulated circuit to power these with low amperage at 110v. My amp gauge shows about 600ma when directly powered (getting super hot), BUT I got it down to ~260ma by wiring a 6 watt light bulb in series and the coil buzzes but still seems to open enough and stays completely cold. I don't want to have a hot/fragile 6 watt light bulb inside my machine. Is there an easy way to use some kind of inductor to drop current without generating heat and wasting power? I know there is some way to calculate it with my known coil impeadance. I don't want to make a whole circuit just to power this thing. I am temped to find one that is 12v DC and use an old wall wart to power it but then that one may get hot too since I am sure a 12v one would have a very low impeadance anyway. Plus I already found & bought all the fittings to plumb this thing inside my machine.