A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:

let B work in =xdays
let A work in =3*xdays
A+B=x+3x....

Inasmuch as Aleph inadvertently gave the answer away -- let's move on to the next exercise, Ok!?

 

@RRITESH KAKKAR

Tapping fingers...

Absenteeism and 'doing runners' is both poor scholarship and, I might add, straight up rude!

The next problem - please???

 

A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?

both are different.

A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:

 

Start with figuring out how long it would take each of 'A' and 'B' to do the work single handly...

 

A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:

A:B=3:1

 

Hint: Use of the 'simultaneous approach' will make it easier!

 

How to do?

 

A:B=3:1

That's a good start now please write it algebraically (i.e. B/A=3 where A and B represent the 'time to completion' for each worker acting independently) -- The problem with 'ratios' (e.g. A:B) thus stated is that they lack variable-specific magnitude information (À la SWR indication)

Now you've another equation to write...

 

A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:

A is thrice as good as workman as B
this mean A can do job faster than B 3rd rate.
Therefore is able to finish a job in 60 days less than B.
if B take 'x' days A can do
A do in x-60
Working together, they can do it in:
A+B=?
3*1+1=x-60
4=x-60
x=64

 

1) A is thrice as good as workman as B --- Meaning 'A' works exactly three times faster than 'B'
2) But we also know that 'A can finish a job in 60 days less than B'


From stipulation 1 (above): B/A=3
From from stipulation 2 (above): B-A=60

Where A and B = the number of days required for the titular workers to finish the job single-handedly..

Can you take it from here???

 

B/A=3
B=3*A
but this equation is showing B is faster 3 time than A?

 

It's B/A because B takes three times as many days as A

 

ok, we are talking of time here

 

From stipulation 1 (above): B/A=3
From from stipulation 2 (above): B-A=60

Where A and B = the number of days required for the titular workers to finish the job single-handedly..

B=3*A
B-A=60
3*A-A=60
2A=60
A=30
B-30=60
B=90

 

Good!

So - now the question is: how long will it take them to complete the job via a collaborative effort!

 

Where A and B = the number of days required for the titular workers to finish the job single-handedly

how to do this?

 

Good!

So - now the question is: how long will it take them to complete the job via a collaborative effort!

produced by or involving two or more parties working together
that mean
A+B=?
A=30days
B=90days

 

how to do this?

You already did it!

A=30 Days
B=90 Days

So... How long it will take them if cooperating?

 

we can't just add both ?

 

A=30 Days
B=90 Days
60 Days