Convert the two values to rectangular form, add them and convert back to polar form.

thanks i get the answer.

 

So @RRITESH KAKKAR , What's it gonna be? -- Are you feeling like a student today -- or is it to be more lackadaisical nonsense? --- I'm yet willing to assist you on the condition that you are serious about study

why?

 

Actually, i was following this to have more Reasoning power.
http://www.indiabix.com/aptitude/questions-and-answers/

@RRITESH KAKKAR

Inasmuch as that resource is both open and available to everyone -- I'm satisfied that that you were not cheating If you genuinely feel 'working' those problems will be of benefit to you, I'll be pleased to help so long as you attempt to remain focused and make a genuine effort to solve the exercises sans intervention...OK?

 

thanks i get the answer.

If you wish to add polar vectors for a resultant vector use the parallelogram law -- To merely obtain the coordinates of the sum, use the approach elaborated by @Aleph(0) in Post #756 --- My $.02

 

HP you are meaning this when you say law of cosines but I say better to call it triangle law cuz ambiguous terminology, just saying Sorry if bold and symbols don't work
r1*cos(Θ1)+r2*cos(Θ2) ∠ r1*sin(Θ1)+r2*sin(Θ2)
Edit to say I like question cuz it bridge gap of abstract musings and common sense!

r1*cos(Θ1)+r2*cos(Θ2) ∠ r1*sin(Θ1)+r2*sin(Θ2)
r1*cos(Θ1)+r2*cos(Θ2) + ∠ r1*sin(Θ1)+r2*sin(Θ2)

actually i am confused

 

r1*cos(Θ1)+r2*cos(Θ2) ∠ r1*sin(Θ1)+r2*sin(Θ2)
r1*cos(Θ1)+r2*cos(Θ2) + ∠ r1*sin(Θ1)+r2*sin(Θ2)

actually i am confused

And well you should be! -- Actually the second "term" is not an angle!

 

mean?

 

Here it is sans 'tricks and traps'

X(resultant)=r1*cos(Θ1)+r2*cos(Θ2)
Y(resultant)=r1*sin(Θ1)+r2*sin(Θ2)

Got it?

 

yes

 

So... Do you have any particular problems you'd like to work on?

 

right now no.

 

So... Do you have any particular problems you'd like to work on?

i think verbal exercises

 

i think verbal exercises

I agree! -- that seems to be the area in which you require work --- Again, I am willing to assist you with questions from any 'open' pool (such as the one you linked) -- That way everyone will know it's on the 'up and up'!

 

@RRITESH KAKKAR

As per your PM --- Please post exercises here -- That way future readers can benefit and assistance is both 'crowd sourced' and 'peer reviewed'

 

A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :

 

Think of it like this:

'A' does 1/15 of the job per day
and
'B' does 1/20 of the job per day

 

ok, got the mean.
8
15

 

A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only. Then, C alone can do the job in:

A=1/16 B=1/12 of the job per day
A+B+C=1/4
C=1/4-A-B??

 

Think reciprocals

 

of what?