how is right ?!hi full,
Your answer is wrong.
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the question told you the Q output=1Why are you starting yet another thread on this same problem?
Think about what your waveforms are saying. Q0 changes from LO to HI at clock #2 but nothing else changes. Then it changes back to LO at clock #3 placing everything in the exact same state it was in after clock #1. But then, magically, at clock #4 both Q0 and Q2 change. Does that make sense?
Be methodical about your work. Don't scribble notes on the diagram that are impossible to follow. Make a table that shows the D input values and the state changes for each clock.
PLEASE! Just use the normal font. We are all capable of reading and don't need the written equivalent of shouting at us.the question told you the Q output=1
the intentional Q0 (#clk 0 from 1 in waveform) and (#clk 1 from 0 in waveform) ......
the Q1 J0 - K0 => no change ,all the clks 1.....
my answer Q0 and Q1 it is true
but Q2 and Q3 I don't know true or error!
3 days in this questionhi,
Sorry, its still not correct.
Consider FF1 input, before the 1st Clock, the JK are both Low. [ because /Q of FF3 is Low]
After the rising edge of the 1st Clock pulse, the /Q of FF3 will go High, but the Q output of FF0 goes Low, so JK into FF1 is still Low.
After the 2nd Clock pulse, Q of FF0 will go high again. this means the AND gate feeding FF1 has a High from Q of FF0 and /Q of FF3.
So the 3rd clock pulse will toggle FF1 1 to Low.
You can work out the remaining cycles from this Hint.
Look at the attached 4027 image
hi full,3 days in this questionthere isn't answer true#
Several times you have been asked to include the waveforms for the control inputs to the flip flops. That will let us see exactly where you are going wrong so that we can point it out. It's just three signals. But you won't do it. Why not?I think now true![]()