I've posted about my generator project a couple of year ago; it's sat idle from then until last week. It's going to be a PTO generator, powered by the rotating shaft coming out of the back of my tractor. This is the typical arrangement (not my picture):

This is where I'm at so far:

I want my generator to serve double duty as a PTO dynomometer.
Please don't suggest I measure electrical power output and calculate mechanical load. That is not what I want to do.
I want to measure physical torque and physical RPM of the PTO shaft.
So here's the idea I'm playing with (side plates of belt drive assembly shown in blue glass for clarity, actually steel):

Instead of a gearbox, I'll have a belt drive, and instead of being rigidly bolted, it won't be fastened to anything. It will be "free"/"floating," hanging from bearings off of the generator input shaft, such that if I were to hang a pipe wrench off the PTO shaft and put some weight on it, (assuming the generator rotor were locked or providing some appreciable resistance) the whole belt drive assembly would rock to the side:

So if I were to put a load cell (red cylinder) exactly level with the PTO shaft:

since the center distance between pulleys is exactly 1ft, that load cell should read out directly in ft*lbs! Right? of course? ...
The more I think about it, the less convinced I am, but I'm not sure why. My intuition-only physics is failing me; I need some educated physics feedback.
My confidence starts to falter when I ponder whether I would be measuring torque before losses or after. There will be some losses in the belt drive. Would this setup yield the torque output from the tractor's PTO, or the torque experienced by the generator shaft? and spiderweb cracks in my understanding branch out from there.
Depending on answer to that, how do the losses manifest? Is there a counteracting force from the generator shaft?
How does this tite-reach ratchet extender work? and why? Does its existence shoot my idea out of the water?
Would this even work at all, forgetting about losses?

This is where I'm at so far:


I want my generator to serve double duty as a PTO dynomometer.
Please don't suggest I measure electrical power output and calculate mechanical load. That is not what I want to do.
I want to measure physical torque and physical RPM of the PTO shaft.
So here's the idea I'm playing with (side plates of belt drive assembly shown in blue glass for clarity, actually steel):



Instead of a gearbox, I'll have a belt drive, and instead of being rigidly bolted, it won't be fastened to anything. It will be "free"/"floating," hanging from bearings off of the generator input shaft, such that if I were to hang a pipe wrench off the PTO shaft and put some weight on it, (assuming the generator rotor were locked or providing some appreciable resistance) the whole belt drive assembly would rock to the side:


So if I were to put a load cell (red cylinder) exactly level with the PTO shaft:


since the center distance between pulleys is exactly 1ft, that load cell should read out directly in ft*lbs! Right? of course? ...
The more I think about it, the less convinced I am, but I'm not sure why. My intuition-only physics is failing me; I need some educated physics feedback.
My confidence starts to falter when I ponder whether I would be measuring torque before losses or after. There will be some losses in the belt drive. Would this setup yield the torque output from the tractor's PTO, or the torque experienced by the generator shaft? and spiderweb cracks in my understanding branch out from there.
Depending on answer to that, how do the losses manifest? Is there a counteracting force from the generator shaft?
How does this tite-reach ratchet extender work? and why? Does its existence shoot my idea out of the water?
Would this even work at all, forgetting about losses?