Hi all,
I am designing a "Plinko" game board, with an rgb led embedded into each of the clear acrylic pegs. My question is do I have to solder in 3 resistors per led for every peg, or can I run all of the red wires together, connect to a much larger resistor, and do the same for the red, and green, so that I only have 3 resistors total. My leds are common anode, red vf is 2.2, blue vf is 3.3 and green vf is 3.3. I am running from a 12v controller, so at 20 milliamps my resistor values are 490 ohms for red, and 435 ohms for blue and green. For a single led, I would need 1/4 watt resistors P = (12-2.2) * .02 = .196 Watts, so if I bundle all the leads and I am running 100 leds, could I use a 490 ohm, 20 Watt resistor instead? I think that the theory is sound (and it's a lot less work) What do you think? If this is a possibility, and I can only find 20 W resistors in 250 ohms, I could just run through them in series and the resistance adds, right? Thanks!
I am designing a "Plinko" game board, with an rgb led embedded into each of the clear acrylic pegs. My question is do I have to solder in 3 resistors per led for every peg, or can I run all of the red wires together, connect to a much larger resistor, and do the same for the red, and green, so that I only have 3 resistors total. My leds are common anode, red vf is 2.2, blue vf is 3.3 and green vf is 3.3. I am running from a 12v controller, so at 20 milliamps my resistor values are 490 ohms for red, and 435 ohms for blue and green. For a single led, I would need 1/4 watt resistors P = (12-2.2) * .02 = .196 Watts, so if I bundle all the leads and I am running 100 leds, could I use a 490 ohm, 20 Watt resistor instead? I think that the theory is sound (and it's a lot less work) What do you think? If this is a possibility, and I can only find 20 W resistors in 250 ohms, I could just run through them in series and the resistance adds, right? Thanks!