Hello every one!
I have RGB strip led and i should use 2 batteries of 18650 (Li-ion) to turn it on. this strip have 12vdc and maximum current is 4A.
I want to build/buy a booster that Vin=3.7v dc or 7.4v dc (2 batteries of 18650 in parallel or series), Vout=12 v dc , Iout=3-4A.
I will glad to hear your comments

 

Jist use 3 cells in series, 12.6V.

 

Hello every one!
I have RGB strip led and i should use 2 batteries of 18650 (Li-ion) to turn it on. this strip have 12vdc and maximum current is 4A.
I want to build/buy a booster that Vin=3.7v dc or 7.4v dc (2 batteries of 18650 in parallel or series), Vout=12 v dc , Iout=3-4A.
I will glad to hear your comments

Read very carefully and learn something

1. 12 VDC x 4 Amperes = 48 Watts of Output Power
2. Any conversion scheme you use will be less than 100% efficient
3. Let us assume it came from an undisclosed country and is 80% efficient
4. 48 Watts / 0.80 = 60 Watts of Required Input Power
5. 60 Watts of Input Power @ 3.7 VDC ≈ 16.2 Amperes
6. It gets worse as the battery discharges, @2.8 VDC, it requires 21.4 Amperes
7. Your battery would need something like 100 Amp-Hours to keep the strip lighted all night
8. Do you still think this is a good way to go?

 

Read very carefully and learn something

1. 12 VDC x 4 Amperes = 48 Watts of Output Power
2. Any conversion scheme you use will be less than 100% efficient
3. Let us assume it came from an undisclosed country and is 80% efficient
4. 48 Watts / 0.80 = 60 Watts of Required Input Power
5. 60 Watts of Input Power @ 3.7 VDC ≈ 16.2 Amperes
6. It gets worse as the battery discharges, @2.8 VDC, it requires 21.4 Amperes
7. Your battery would need something like 100 Amp-Hours to keep the strip lighted all night
8. Do you still think this is a good way to go?

thank you,
I must use 4 batteries in series to obtain 2.5A at input