Hi dl324,How about an LED to indicate power on/off? You could operate it at a low current to minimize power.
My circuit is just a low power PIR sensor from Panasonic, which is powered by a digital pin. A pic and two push button. And a solid state relay. Plus the usually passive stuff.You could use a cmos variant of a 555, but the charging current of the timing cap will still be there. Can you post your circuit?
Also note the flipdot needs at least 12V to flip, so you might need some charge pump to get that.
I wonder if you could somehow use light-focusing, fiber optic plastic like the stuff that is used in gun sights. This would take advantage of ambient light to produce an intense dot. Of course the challenge is how to toggle the appearance from one state to another.But in my case, the indicator also needs to be easily visible from distance during the day..
You probably can't get much better than an LED, regular types are typically 20mA but you can get ultra-efficient 3mm types that at least give an indication at only 2mA.Hi guys
I am looking for an indicator that draws little or no power. (for my battery power device) Any idea? The indicator will have two state, to show the device is operating, or to show the device is power off.
Thanks guys!!
Sorry about that, I should have include more information. But all of you inputs are appreciated!It would be helpful if you provided as much detail as possible when seeking assistance...
Low power and visibility from a distance during daylight are typically conflicting requirements..
I am using lithium battery, so it's about 3.3V normally.What is your battery voltage?
It sounds like it's not something I can buy off the shelf, but it's a really cool idea, I would like to look into it.I wonder if you could somehow use light-focusing, fiber optic plastic like the stuff that is used in gun sights. This would take advantage of ambient light to produce an intense dot. Of course the challenge is how to toggle the appearance from one state to another.
I am hoping on my average current for the indicator is under 50uA. my circuit draw is under 10uA at sleep. The circuit is sleeping all the time. For a designer, my circuit doesn't power off, the two states that the indicator needs to show to an end user is 1) device is sleeping but interrupt enable.(aka operating); 2)device is sleeping but interrupt is disable. (aka for a user, power off).How much average current can you tolerate for the indicator?
What is the battery and what does the rest of the circuit draw?
I still think the flip dot indicator will draw less current on average / day, as my device will likely operating ~12 hours/day. (Indicator needs to show the device is operating). But i the indicator only needs to change state 2-4 time, so on average, the flip dot indicator draws virtually no power. Am I correct?You probably can't get much better than an LED, regular types are typically 20mA but you can get ultra-efficient 3mm types that at least give an indication at only 2mA.
If you really need a micropower solution, try a couple of CMOS NAND gates wired as an astable - make the mark space ratio very unequal so the LED only blinks breifly during its on period - even with 50/50, the LED would only be drawing current half the time.