Loudspeakers [A,B,C] and [D,E,F] are wired in parallel. Then the set of loudspeakers [A,B,C] are wired in series with [D,E,F]. If the total rating of the system is 1350W @ 5.3 Ohms, What is the power and impedance of each loudspeaker?

 

Home work ?

replace them with resistances, and re draw the circuit,
what do you see,
resistors a // b // c = d // e // f

so call a // b // c resistance A , and d // e // f resistance B

And we know A and b are in series.

so what is the value of A ?

Once you know A,
then you know a // b // c = A , and a, b ,c are all same,
so you know value of a etc.


re power , the answer is simple,

but , to work it out,

you know the power in , you know the total resistance,
you now know the resistance of each unit,

hence you can work out the V across and the current through each resistor,
hence you can find the individual powers.


BTW:

if this is a real set of speakers,
then impedance you measure with a meter is not the same as real impedance / resistance,

 

Speakers have a boomy sounding resonance like a bongo drum. The resonance is damped by the extremely low output impedance of a modern amplifier (0.04 ohms or less). Your speakers in series have poor resonance damping.