Good day,
I have a project with the use of LM339 comparators to operate a seven segment display (flash adc and encoder) and I am having problems with understanding it specifically the comparator part.
I made a Voltage Divider Reference Source Comparator circuit as reference.
(See attached File)
As seen from the figure, the opamp operates on a 5V battery (Vcc=5V).
It has two analog signals (Vin = 5Vrms and Vref=3Vrms).
I read that no matter what input signal there is, as long as it compares either the positive or negative input as a higher amplitude, the output could be around +Vcc or -Vcc. But as seen from the simulation, the output is at 2.248uV at the 1ohm load. What is the reason for this? Did I miss something? Is my understanding only for ideal situations? But even if it isn't ideal, should the output voltage be that low? Thank you for listening and please tell me if you are confused, I will clarify as best as I can.
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I have a project with the use of LM339 comparators to operate a seven segment display (flash adc and encoder) and I am having problems with understanding it specifically the comparator part.
I made a Voltage Divider Reference Source Comparator circuit as reference.
(See attached File)
As seen from the figure, the opamp operates on a 5V battery (Vcc=5V).
It has two analog signals (Vin = 5Vrms and Vref=3Vrms).
I read that no matter what input signal there is, as long as it compares either the positive or negative input as a higher amplitude, the output could be around +Vcc or -Vcc. But as seen from the simulation, the output is at 2.248uV at the 1ohm load. What is the reason for this? Did I miss something? Is my understanding only for ideal situations? But even if it isn't ideal, should the output voltage be that low? Thank you for listening and please tell me if you are confused, I will clarify as best as I can.
Moderators note : shown image full size
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