LC Band Pass Filter Network

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Cryptokyo

Joined Sep 25, 2016
1
Hello everyone,

I have attached the 3 questions I am wrestling with.

For 10 I used the equation: \(f_{0}=\frac{1}{2\pi\sqrt{LC}}\) to obtain \(f_{0}=50.3kHz\)

For 11 I used the equation: \(R_{D}=\frac{L}{r_{L}C}\), with \(r_{L}=100\Omega\) to obtain \(R_{D}=100k\Omega\)

For 12 I treated it as if it was a voltage divider so: \(V_{out}=1\times\frac{100k\Omega}{100k\Omega + 10k\Omega}=0.91V\)

I feel as if this is incorrect. Can anyone just give this a quick check over as I am relatively new to AC circuits.
LC Network.JPG
 

MrAl

Joined Jun 17, 2014
11,486
Hi,

Those answers look correct given a small tolerance because of numerical truncation to the given number of digits.
 
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