I have succesfuly made a circuit and its working but whenever i plug in the circuit the relay turn on automatically without even pressing the remote button. I dont know whats wrong with the circuit.

 

You need a power up reset and another npn driver for LED, it means that you should adding another 4.7K and NPN to drive the 470 resistor and LED, why you should do that, because the output current is too less from Pin 2.

Or you can try to moving 470 and LED to in parallel with the coil of relay, it will save the 4.7K and NPN bjt..

 

The power up reset as:
In series with a 47K/0.25w resistor between Pin 4 and Pin 15, and connecting a 0.1uf capacitor from Pin 15 to +6V.

 

Thank you for your help, i will try and will tell you if it helped ...

 

Actually the problem is not with the led ... its with the realy ... When i completely turn off the circuit and then turn it back on, the relay automatically turns on and the bulb connected to it turns on ...

 

Where is the relay? I see what appears to be a transformer in the upper right?

Is that supposed to be the relay? If that is the relay, which contact is moveable, which contacts are the NO/NC ones?

 

no, its a relay ... and the pin to which the bulb is connected is the NC one ...

 

I did what u said but still not working properly ... Still when i turn off and then on the circuit the relay turn on and then i have to turn it off with remote ...

 

Try adding a small capacitance to the collector of the relay driver. Might be power on transients. 1 uf would be enough to see if that is the defect.
Try it on the +6 volt power side of your relay coil first.

 

ok let me see what happens

 

You should have a back-emf suppression diode (reverse-polarised) across the relay coil to protect the transistor. Also, a 0.1uF ceramic cap should be connected directly between the supply pins of the IC to decouple it.
What is the purpose of the 10uF cap? It will slow down the edges of the clock pulse and could make the clocking unreliable.
Your LED would be better driven from the transistor collector rather than from the IC (which has very limited output current sourcing capability).

 

no, its a relay ... and the pin to which the bulb is connected is the NC one ...

The N/C contact will energize the bulb with the relay Off.
So, it is likely the bulb will light up on power-up.

To clarify, when you say the relay is On at power-up, is the LED connected to the output (pin 2) also On at this time?