Hi. Can someone please explain the output at pin 2 when the inverter (SN74LV06ADBR) is high? I thought it toggles between 0 and 3.3V, but a friend told me that when the output is high, the voltage at pin 2 is not 3.3V, and the inverter has a high impedance so it is at some unknown voltage with very little current. Please see the first attached photo below. However, when the output is low, the voltage at pin 2 is 0V.
2. The goal of the new circuit is to turn on an LED when SERVO_ON_LED_N is 0 (the output at pin 2 of the inverter) and turn off an led when the output at pin 2 is high and at high impedance. Please see the second attached photo( the inverter and the 1k resistor is the same as in the first attachment) I understand how the LED will turn on when the signal is 0V at low, but how will it turn off when the output is high at the inverter? I would love it if someone could explain how that proposed schematic would turn the LED on and off at the right time based on the previous schematic. Thank you so much.
Update: the last photo is a more zoomed-out one.
2. The goal of the new circuit is to turn on an LED when SERVO_ON_LED_N is 0 (the output at pin 2 of the inverter) and turn off an led when the output at pin 2 is high and at high impedance. Please see the second attached photo( the inverter and the 1k resistor is the same as in the first attachment) I understand how the LED will turn on when the signal is 0V at low, but how will it turn off when the output is high at the inverter? I would love it if someone could explain how that proposed schematic would turn the LED on and off at the right time based on the previous schematic. Thank you so much.
Update: the last photo is a more zoomed-out one.
Attachments
-
18.4 KB Views: 22
-
50.6 KB Views: 20
-
79.6 KB Views: 21