That is almost right out of the data sheet. Yes, it quotes only split supplies but an example in the data sheet shows single supply operation in a similar circuit. Have you tried modeling it with another (simpler) IC that says it is designed for single supply operation?Thanks for the reply. I want to use the IA with a bridge. With reference to the schematic below, since all resistors are equal, shouldn't the output of the IA be 0V?
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When I connected pin 4 to -12V using the circuit shown in post #4, the meter measures -15VTry it with +- split supplies. The data sheet doesn' t say anything about its rail-to-rail operation with a single supply. In fact, the data sheet implies that split supplies are required.
Thanks all for the replies. I did as JohnlnTX suggested (pin 5 set to 6V) and it worked.One problem is that Vref pin 5 is strapped to what the amp considers the negative PS rail (Vs). The specs say this pin should be 1.6v above Vs. Try setting it to Vcc/2 for single supply operation.
Okay, assuming the simulator is wrong ... what do you get if you actually breadboard the design?I think there is something wrong with the simulator or with the AD621 model: the amp output at pin 6 is apparently -3.49V with a single-polarity supply !
re: returning Ref to V/2 ... Super! That agrees with the example in the data sheet.One problem is that Vref pin 5 is strapped to what the amp considers the negative PS rail (Vs). The specs say this pin should be 1.6v above Vs. Try setting it to Vcc/2 for single supply operation.
I've no idea. I've never had/used an AD621.what do you get if you actually breadboard the design?
Very pricey, about $10 a piece. Bipolar input. Well less than 1 MHz frequency range. I would need a good reason to justify it. Low noise, low CMRR, precise gain?I've no idea. I've never had/used an AD621.
Only you know what precision, linearity and stability you need.Is it really needed in this design?