input current of single phase controlled bridge rectifier

t_n_k

Joined Mar 6, 2009
5,455
It's not that simple, since the current depends on the type of load. For a purely resistive load then a possible solution would be

\(I_{rms}=I_m \sqrt{\frac{1}{2}-\frac{\theta}{2 \pi}+\frac{sin(2 \theta)}{4 \pi}}\)

where Im=peak current & θ= firing delay angle
 
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