Simply put, "Q" of a resonant circuit tells you how sharply tuned the circuit is. It will also tell you the amount of voltage increase at the junction of L and C.Wow, what an amazing group I've stumbled upon here! I was not prepared for such thoughtful and thorough responses. I can't thank you all enough for your active involvement in my pursuit of understanding. Thank you, thank you!

MrChips: I was confused at first as my browser font makes the symbol for π look like a lower case N, but quickly realized it was Pi (which is tomorrows date, 3/14/15). After writing down your examples and graphing them out on the nomogram, the pattern is starting to stand out to me more, but it will take much more repetition and practice on my end before it becomes engrained as second nature. Thank you for illustrating it as such.

KL7AJ:

Opening up my copy of J Carr's 'secrets of RF circuit design' I find the formula: F = 1/2π√LC (pardon me if my notation is incorrect, I am unfamiliar with the correct way to rewrite (type) the formula). I am taking this formula into consideration as I continue to reach for an understanding.

So, and please bear with me here, with your example of 1H and 1F at 0.16(0.159)Hz, the reactance of both L & C is 1-ohm. Is this correct?

"is there any reason for any SPECIFIC values of L/C ratio?" Hmm. Not sure if I correctly understand what your asking but the first thing that comes to mind is that one would seek specific values for the L/C ratio depending on the type of circuit stage being designed and to reach a chosen impedance for matching the stages. I think I will let you give me another clue before I get too far off track with that question.

This is fun!!

studiot: "Since the scales are all log it could be used as a pattern to rescale any log-log paper by drawing ruled lines."

Aha, I see! This was what I was wondering, and have pleasantly received a more thorough lesson along the way. I hope I can take what i learn here and apply it to rescaling these log graphs. Very cool.

KL7AJ: "If ALL we had in our circuit was a pure resistance and pure reactance, we could pick any L/C ratio we like, and come up with a resonant circuit at our chosen frequency of interest.

However, in the real world, we either have a resistive load, into which we're trying to do real work....or we have imperfect components."

So, maybe I wasn't too far off with my answer to your first question? I think I see what you are getting at.

"Capacitors tend to be closer to pure components in most cases."

Interesting and new to me.

"For a simple LC series circuit, the value of reactance will determine the resonant circuits "Q" at resonance. Q is defined as the ratio of reactance to resistance. Therefore, we will find that a larger L/C ratio gives us a larger Q circuit. This is not strictly true for PARALLEL circuits, however."

Alright, I knew that 'Q' was sneaking up on me and I'm mighty excited and eager to start taking it into consideration. I have a GDO that I hope to utilize for measuring Q but I believe there may be other ways for measuring Q. I'll keep the test gear unplugged until I start to develop a more intuitive understanding of the nature of LC resonant circuits.

Okay, so does the reactance / impedance / frequency formula & the graph apply the same to both parallel and Series LC circuits? Do I need to worry about the difference between the two yet, as I am becoming more familiar with the relation between Z,XC,XL & Frequency?

I've been studying an article from Ham Radio Magazine, Feb 1977 on Bandspread calculation techniques, that I am hoping will give me a more thorough understanding of what it is I am seeking here.

I can't thank you guys/gals enough for taking time to communicate with me about such a fascinating and fun topic. I never expected such kind, enthuesiastic and informative replies and for this I am very grateful.

If you have SPICE, you can model this simply. Wire up an ac voltage source, an inductor, a capacitor, and a resistor. Next put a voltage probe at the junction of L/C, which would be node 2. Run an AC sweep test. The voltage you see at node 2 will be your supply voltage times reactance/resistance, or supply voltage times Q. This tells you how much voltage step up you can have in a resonant circuit.

But don't take SPICE's word for it! Build the circuit and see!

Eric