L=μAln^2

Values I used for equation

μ= 4π*10^(-7) T/amp m

A= 2π(.493)^2 = 1.527in^2 = .0387 m^2

l = .2032m

n = 258/.2032 T/m = 1269.685 T/m (what is the appropriate unit for n?)

So I have

L = 4π*10^(-7) T/amp m * .0387 m^2 * .2032m * (1269.685)^2 T/m

L = 4.863^-8 (Tm^3)/amp *327578.719 T^2/m

L = .016 T^3m^2/amp

The next calculation I did was

X=2πfL

f = 60 hz

L = .016 H

X= 2π * 60 * .016

X = 6.031

SO finally to find my current I can do

120v (output of my inverter)

6.031 ohms

120/6.031 = 19.897 amps

Does this look about correct?

I found the equations from these sites in case people are wondering.

http://www.allaboutcircuits.com/textbook/alternating-current/chpt-3/ac-inductor-circuits/

http://physics.info/inductance/