I did the following calculation
L=μAln^2
Values I used for equation
μ= 4π*10^(-7) T/amp m
A= 2π(.493)^2 = 1.527in^2 = .0387 m^2
l = .2032m
n = 258/.2032 T/m = 1269.685 T/m (what is the appropriate unit for n?)
So I have
L = 4π*10^(-7) T/amp m * .0387 m^2 * .2032m * (1269.685)^2 T/m
L = 4.863^-8 (Tm^3)/amp *327578.719 T^2/m
L = .016 T^3m^2/amp
The next calculation I did was
X=2πfL
f = 60 hz
L = .016 H
X= 2π * 60 * .016
X = 6.031
SO finally to find my current I can do
120v (output of my inverter)
6.031 ohms
120/6.031 = 19.897 amps
Does this look about correct?
I found the equations from these sites in case people are wondering.
http://www.allaboutcircuits.com/textbook/alternating-current/chpt-3/ac-inductor-circuits/
http://physics.info/inductance/
L=μAln^2
Values I used for equation
μ= 4π*10^(-7) T/amp m
A= 2π(.493)^2 = 1.527in^2 = .0387 m^2
l = .2032m
n = 258/.2032 T/m = 1269.685 T/m (what is the appropriate unit for n?)
So I have
L = 4π*10^(-7) T/amp m * .0387 m^2 * .2032m * (1269.685)^2 T/m
L = 4.863^-8 (Tm^3)/amp *327578.719 T^2/m
L = .016 T^3m^2/amp
The next calculation I did was
X=2πfL
f = 60 hz
L = .016 H
X= 2π * 60 * .016
X = 6.031
SO finally to find my current I can do
120v (output of my inverter)
6.031 ohms
120/6.031 = 19.897 amps
Does this look about correct?
I found the equations from these sites in case people are wondering.
http://www.allaboutcircuits.com/textbook/alternating-current/chpt-3/ac-inductor-circuits/
http://physics.info/inductance/