Hey! I have worked out the characteristic equation using det(A-λI) = 0,
where
\(A = [\frac{a b}{c d}]\) (ignore the line, it is a matrix but don't know how to do it in LaTex so used the fraction function)
So my characteristic equation is:
\(\lambda^2 -tr(A)\lambda + det(A) = 0\)
where \(tr(A) = a + d\) and \( det(A) = ad - bc\)
How would I solve the eigenvalues for the above function? I understand that it is the values of \(\lambda = 0\) but not sure how to make the function to to zero in this general case... Thanks!
where
\(A = [\frac{a b}{c d}]\) (ignore the line, it is a matrix but don't know how to do it in LaTex so used the fraction function)
So my characteristic equation is:
\(\lambda^2 -tr(A)\lambda + det(A) = 0\)
where \(tr(A) = a + d\) and \( det(A) = ad - bc\)
How would I solve the eigenvalues for the above function? I understand that it is the values of \(\lambda = 0\) but not sure how to make the function to to zero in this general case... Thanks!