How solve for current I?

WBahn

Joined Mar 31, 2012
24,693
Have you considered going through and simplifying the network by combining series/parallel combinations of resistors?
 

WBahn

Joined Mar 31, 2012
24,693
You might also consider identifying the voltages on as many nodes as you can before doing anything else.
 

WBahn

Joined Mar 31, 2012
24,693
Hint: By inspection, you can determine that the current is the same as you would get if the batteries were 2V each and the resistances were 5 Ω each.
 

shteii01

Joined Feb 19, 2010
4,667
Yeah, what W said. There is a bunch of parallel and series resistors. You should be able to simplify the circuit.
 

WBahn

Joined Mar 31, 2012
24,693
Ideally yes. But there are lots of schematics and schematic packages that take the position that if either of the two top approaches are taken to show non-connected crossing wires that that means that the bottom can be used to show connected crossing wires.

In this case there are not instances of lines that cross without making a junction that are shown in an unambiguous way, so we have to guess. Assuming that they are connected makes the analysis of the circuit possible by inspection, which I suspect was the intent.
 

The Electrician

Joined Oct 9, 2007
2,737
At first glance, one might think that so many batteries make it more complicated, but in fact the large number of batteries make it possible to work across the network one mesh at a time, with the batteries providing constraints allowing for solution by inspection.
 
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