Im not sure how to get the answer for this question and cant find anything that helps. Any help would be apprecitied.

 

This is Homework Help, not Homework Done For You. You need to show YOUR best attempt at a solution. That gives us a starting point from which to help you identify where you are going wrong and help guide you toward the answer.

Hint: Just tabulate the real and reactive powers, add them up, and convert to apparent power and power factor.

 

not sure how to go about this problem this is what i have tried don't know where im going wrong
real power = kva x pf
so i did 100kva x .9pf =90kw for the induction motor being added
and 400kva x .75pf =300kw
add together 300kw +90kw= 390kw
new kva is 100kw / .9 = 111.1kva + 400kva = 511.1kva
then 390kw / 500kva = .78 new power factor

 

Note that the additional motor, in either case, is NOT 100 kVA -- it is 100 kW. They are giving you the real power load of the motor along with it's power factor.

 

Also, note that you can't add kVA values together because kVA is apparent power that makes no allowance for phase angle.