Hello, I use some software called feedback analysis, and i use that site to find the resosnant frequency is 11.25Mhz, but i still dont understand how it workshi michael,
Have you calculated the resonant frequency of that series RLC tuned circuit.?
E
BTW: From where did you get that circuit.?
EDIT:
This link may help.
https://www.allaboutcircuits.com/tools/tank-circuit-resonance-calculator/
Hi, yes is for rf design, but i dont see so much changes when i change the frequencyWhat is the transistor type, and what is the application? Is this an RF Power output stage? The RLC base to collector can sometimes be used to 'neutralize' the transistors base - collector capacitance. A link to the origin of this circuit would be helpful.
I sim'd it in LTSpice and I didn't see any variations in the passband or phase either. I think with that 1K resistor there isn't enough feedback to make any difference.Hi, yes is for rf design, but i dont see so much changes when i change the frequency
thnx man, but i dont understand, what they do LC Tank, you can use only one resistor for feedback, why also LC, is possible a lttle bit to explain me more in detail, i know they resononate at 11.25Mhz, but more i dont know, and also my circuits he dont have a Resistor 47k, do you want to send you my software,you understand more than me?I sim'd it in LTSpice and I didn't see any variations in the passband or phase either. I think with that 1K resistor there isn't enough feedback to make any difference.
(I used a 15 volt source on the collector and used a 47k resistor from +15 to the base to bias the transistor - sim'd with a 2n3904)
Hello, but me i dont understand what they do lc, you can use only one resistor feedback, what for changes they do lcBelow is the LTspice simulation of the circuit similar to Ylli's version for 1Ω, 10Ω, 100Ω, and 1kΩ values of R1.
L1C1 has no discernable effect on the gain for R1=1kΩ (green trace), the original value, but shows increasing rolloff as R1 is reduced to 1Ω (yellow trace).
View attachment 155284
Thnx Man, i am reading this article….hi michael,
Look at this link, note the response plot of that series L C circuit.
You see at resonance the series impedance is the lowest value, this means the negative feedback is at a maximum, so the circuit gain is at a minimum.
https://www.electronics-tutorials.ws/accircuits/series-resonance.html
Look at the Yellow line plot in post #11, shows the gain
Update: you recall that you calculated Fres ~ 11.25MHz, compare that with the Yellow plot.
E
EDIT:
Clip from that link.
View attachment 155296
Hi, i read fast the article, at resonance frequency current is at maximumhi michael,
Look at this link, note the response plot of that series L C circuit.
You see at resonance the series impedance is the lowest value, this means the negative feedback is at a maximum, so the circuit gain is at a minimum.
https://www.electronics-tutorials.ws/accircuits/series-resonance.html
Look at the Yellow line plot in post #11, shows the gain
Update: you recall that you calculated Fres ~ 11.25MHz, compare that with the Yellow plot.
E
EDIT:
Clip from that link.
View attachment 155296
Like i read fast at resonance frequency, the current is at maximum, of xl xc act like a short, only the resistance stay to calucalte, so it dependes how small of large the value of R is, and the current depends on R, I=V/R os is R small more current is R high low current RIGHT?hi michael,
Look at this link, note the response plot of that series L C circuit.
You see at resonance the series impedance is the lowest value, this means the negative feedback is at a maximum, so the circuit gain is at a minimum.
https://www.electronics-tutorials.ws/accircuits/series-resonance.html
Look at the Yellow line plot in post #11, shows the gain
Update: you recall that you calculated Fres ~ 11.25MHz, compare that with the Yellow plot.
E
EDIT:
Clip from that link.
View attachment 155296
I think i understand, like you say, "Look at the Yellow line plot in post #11, shows the gain", i see the result, of graph 1Ω, 10Ω, 100Ω, and 1kΩ values of R1.hi m,
In that circuit a 1k resistor is so large compared to the L and C impedances near resonance, it is 'dominant' so it masks out the effect of the LC.
As the R value is reduced, the LC impedances are effective to a greater degree.
Do you follow OK.?
E
Ohh Man sorry i forget i did not get answer about L2 and R2, what does do L2 or what makes L2 and R2I think i understand, like you say, "Look at the Yellow line plot in post #11, shows the gain", i see the result, of graph 1Ω, 10Ω, 100Ω, and 1kΩ values of R1.
yes i think i understand now, because i have special sofware, it tells everything about gain and impedance and losse, you just have o put one value for the rest he do, and i dont understand how it works, but now i understand so now is easy to do experments
Thnkx a lot
by Luke James
by Luke James
by Luke James