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Hello!
I am building a calculator by using "Logic Gate Simulator"(http://www.kolls.net/gatesim/)
I have, so far, successfully build from input section to memory and BCD adder unit(HEX adder + BCD converter)
and now I am trying to build BCD subtractor and I think I am almost their.
(I attached a picture of my HEX-BCD logic)
The main role of HEX-BCD is prevent output from going any higher than 1001(BNR).
and the HEX-BCD logic should be turned on ONLY when...
1. A - B < 0
and
2. Circuit is borrowing a bit(when the Blue circle is ON)
I confirmed the logic was working by subtracting A(1 to 9) - B(9).
Then I tested it with A - B(A>B) condition, then I found an error
As you can see in my picture, 5 - 1 should turn 3rd significant bit, however, it is suppressed because of my bad logic...
When I tried "3 - 9" showed me "4" as correct answer, with borrowing a bit so 3rd bit is working when blue lines are at HI.
Sorry for bad wiring..that is the one problem of that program D:
and you can ignore OR gate. They are only there to connect more than one outputs to an input port.
(The program does not allow to connect "wire-to-wire" or "more than one output-to-one input")
If anyone can correct my problem or knows better HEX-BCD logic, I am ready to listen!
Thank you!
I am building a calculator by using "Logic Gate Simulator"(http://www.kolls.net/gatesim/)
I have, so far, successfully build from input section to memory and BCD adder unit(HEX adder + BCD converter)
and now I am trying to build BCD subtractor and I think I am almost their.
(I attached a picture of my HEX-BCD logic)
The main role of HEX-BCD is prevent output from going any higher than 1001(BNR).
and the HEX-BCD logic should be turned on ONLY when...
1. A - B < 0
and
2. Circuit is borrowing a bit(when the Blue circle is ON)
I confirmed the logic was working by subtracting A(1 to 9) - B(9).
Then I tested it with A - B(A>B) condition, then I found an error
As you can see in my picture, 5 - 1 should turn 3rd significant bit, however, it is suppressed because of my bad logic...
When I tried "3 - 9" showed me "4" as correct answer, with borrowing a bit so 3rd bit is working when blue lines are at HI.
Sorry for bad wiring..that is the one problem of that program D:
and you can ignore OR gate. They are only there to connect more than one outputs to an input port.
(The program does not allow to connect "wire-to-wire" or "more than one output-to-one input")
If anyone can correct my problem or knows better HEX-BCD logic, I am ready to listen!
Thank you!
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