While I understand the circuit in general, I have a problem figuring out the exact voltage at which the diode will turn on:
circuit 1: the diode will conduct during negative cycle and pea output will be Vin+3V. As far as turning the diode on, I look at the voltage difference between the DC and since voltage drop across diode is 0.7V, to me it makes sense that diode will turn on once -2.3V (i.e. a more positive voltage appears on the anode)
circuit 2: basically same logic and I get 3.7V to turn the diode on.
problem... this seems to be wrong as per multisim, with the answers reversed, I cannot make any sense of it.
Any explanation would help. Thanks in advance.
p.s. Vout is taken across 1k resistor...
circuit 1: the diode will conduct during negative cycle and pea output will be Vin+3V. As far as turning the diode on, I look at the voltage difference between the DC and since voltage drop across diode is 0.7V, to me it makes sense that diode will turn on once -2.3V (i.e. a more positive voltage appears on the anode)
circuit 2: basically same logic and I get 3.7V to turn the diode on.
problem... this seems to be wrong as per multisim, with the answers reversed, I cannot make any sense of it.
Any explanation would help. Thanks in advance.
p.s. Vout is taken across 1k resistor...
Attachments
-
12.9 KB Views: 43
Last edited: