Consider the following circuit:
http://www.rowand.net/Shop/Tech/images/HeadlightRelayWiringDiagram.jpg
I understand all of it except the part with "to existing wiring harness". I would want to know how the rest of it looks.
I suppose that there are two switches: one switch for the high beam and one dip switch for the low beam. And the switches are connected with one end at the "to existing wiring harness" and the other end to the battery.
Is this the case? Because in this case I do not see the point of using relays. Just have directly the switches instead of the relays.
Or maybe there is something I am missing. The point of using relays is to command with a low current a high-voltage portion of a circuit. So there must be coming low currents from the existing harness and not directly 14V. I'm not sure.
Or maybe you know another better circuit that too includes a battery input, switch, dip switch that I would want to know.
http://www.rowand.net/Shop/Tech/images/HeadlightRelayWiringDiagram.jpg
I understand all of it except the part with "to existing wiring harness". I would want to know how the rest of it looks.
I suppose that there are two switches: one switch for the high beam and one dip switch for the low beam. And the switches are connected with one end at the "to existing wiring harness" and the other end to the battery.
Is this the case? Because in this case I do not see the point of using relays. Just have directly the switches instead of the relays.
Or maybe there is something I am missing. The point of using relays is to command with a low current a high-voltage portion of a circuit. So there must be coming low currents from the existing harness and not directly 14V. I'm not sure.
Or maybe you know another better circuit that too includes a battery input, switch, dip switch that I would want to know.