Why is the voltage across R equal to 6.04 v ?

 

What is your best guess or reasoning?
Max.

 

The function generator is giving a 10-vp
Now shouldn't the output voltage be equal to 10 (assuming ideal diode) ?
and if I want to transfer it to DC value, it'd be equal to 3.1 !

 

The function generator is giving a 10-vp
Now shouldn't the output voltage be equal to 10 (assuming ideal diode) ?
and if I want to transfer it to DC value, it'd be equal to 3.1 !

What does "vp" mean as you used it in your description of the function generator output voltage?

Why are you assuming the diode is ideal? The diagram shows a 1N4001 diode, which is not ideal. If the diode is not ideal, how would you calculate the voltage across R2?

You need to show how you came up with the value of 3.1 (volts, I presume); show your units in electrical quantities.

 

Now shouldn't the output voltage be equal to 10 (assuming ideal diode) ?

You are measuring the voltage with a meter which likely gives the average or RMS value of the rectified voltage (.637 or .707 of the peak).
Look at the voltage with the oscilloscope if you want to see the peak voltage.

If you add a large filter capacitor at the diode output, then you get a DC output equal to the peak minus the diode forward drop.