Fullwave Rectifier Circuit?

Thread Starter

NullPoint

Joined Jul 16, 2011
26
Hi everyone!

I was looking for a good reference fullwave rectifier circuit and came across the one below which is referenced in this TI publication. I've seen a similar circuit before but without the capacitor C1. What exactly does C1 do in this circuit?

The article says it's a "compensation capacitor" and that it "ensures the circuit is stable with A2 in the feedback loop". I'm not sure what that means nor how what value it should be either. The article says to "set the C1 * R1 pole equal to ~1/4 the unity gain of A2".
upload_2018-6-5_19-37-21.png
 

danadak

Joined Mar 10, 2018
4,057
When the diode becomes reversed biased that would open the
feedback loop if there were not C1 closing the loop for AC.

Regards, Dana.
 

Thread Starter

NullPoint

Joined Jul 16, 2011
26
When the diode becomes reversed biased that would open the
feedback loop if there were not C1 closing the loop for AC.

Regards, Dana.
I've used the circuit many times without the capacitor and it seems to work just fine. What kind of behavior would I see when feedback loop is opened?
 

danadak

Joined Mar 10, 2018
4,057
Feedback open potential oscillations. The loop would open when
part goes into slew rate limiting preventing OpAmp to servo diode
into conduction.

Also that cap is inferred in article to have a compensation role for the
other OpAmp, you have to do an ac analysis on its impact on phase margin.

Regards, Dana.
 

Thread Starter

NullPoint

Joined Jul 16, 2011
26
Feedback open potential oscillations. The loop would open when
part goes into slew rate limiting preventing OpAmp to servo diode
into conduction.

Also that cap is inferred in article to have a compensation role for the
other OpAmp, you have to do an ac analysis on its impact on phase margin.

Regards, Dana.
OK. I think I understand now. How do I figure out what value cap to use for C1?

My input signal frequency range is 20-500 Hz.
 
Last edited:
Top