So in the diagram, the 3rd and 4th stage outputs of the J Ks are going to a Nand gate then back to CLR... these would be 4 and 8 of 1 2 4 and 8 = 12 would I do the same concept for Mod 9 and Mod 13..meaning outputs from 1st and 4th stage 1 and 8 = 9 going to Nand gates and back to CLR.....same with 13 1st 3rd and 4th stage = 1 4 and 8 = 13

 

Hello,

The Modulus count is the number of states teh counter can reach.
Basic :
http://scitec.uwichill.edu.bb/cmp/online/P10F/counters.htm
Mod 9 ( BCD ) :
http://scitec.uwichill.edu.bb/cmp/online/P10F/asyn_BCD.htm

These links come from the EDUCYPEDIA:
http://www.educypedia.be/electronics/digitacounters.htm

There are more pages like this on digital electronics :

Digital electronics:
Arithmetic circuits D/A-A/D converters Number systems Codes and decoders Flip flops Technology Counters and registers General overview Technology-CMOS Digital logic Memories Technology-TTL Timers and oscillators

Greetings,
Bertus

 

Multiple posting for answers is rude.

9 = 1001
13 = 1101

That and a little though should give your answer.

 

in order to make a Mod 9...the CLR NEEDS to be hooked up to the Nand gate...which 4 from the stages of the flip flops or 7493 Outs?