Ok, How to do?

System Quality Factor (Q) = √(transformation_ratio-1) {transformation_ratio|transformation_ratio>1}

 

Please think about it! This is not a difficult problem! -- Trust me! You DO have the skills to solve this!

Best regards
HP

 

@RRITESH KAKKAR

To 'nudge' you on to the right track:

Ineloquently: Impedance transformation is (clearly) 'all about' EMF and current 'distribution' among reactors...

 

Impedance of (6+4j) to (50+0j)

I think i have solved these type of Question in exam
but now i don't remember.

i think it was used in alternator generator power generation....

 

In electronics, impedance matching is the practice of designing the input impedance of an electrical load or the output impedance of its corresponding signal source to maximize the power transfer or minimize signal reflection from the load.

 

I think i have solved these type of Question in exam
but now i don't remember.

The nice thing about math/science is that if you don't know or can't recall - you can figure it out!

i think it was used in alternator generator power generation....

Possibly -- It's used a great deal in electronics in general -- and especially in communications!

 

In electronics, impedance matching is the practice of designing the input impedance of an electrical load or the output impedance of its corresponding signal source to maximize the power transfer or minimize signal reflection from the load.

Rather than 'surfing' for an answer -- please focus on the problem! -- It really isn't that difficult!

 

(6+4j) to (50+0j)

Can't do..

 

(6+4j) to (50+0j)

Can't do..

Start with transforming (6+0j) to (50+0j) --- As I said, you may compensate for Port 1's reactance afterward

 

(6+4j) to (50+0j
Transform to what?

 

(6+4j) to (50+0j
Transform to what?

The network impedances (each 'end') will, of course, be the conjugates of the port impedances -- So 'looking into' each end of the network (other end correctly terminated) we'll 'see' (6-4j) and (50-0j) --- of course the impedance of the 'end' corresponding to the nonreactive port is 50Ω any way you figure it

 

Why it is negative?
What we get from it??

 

Why it is negative?

To go all 'lowbrow' on ya -- To compensate for the reactance...

 

How to solve it?
What is it advantages?

 

How to solve it?

Start by considering the 'laws' regarding EMF and current distribution among components of RLC networks -- especially at resonance...

What is it advantages?

Impedance transformation is fundamental to electrical engineering (at least!)...

 

Ok, first i will read it.

 

Ok, first i will read it.

Read what?

 

It process what is it ?

 

Start by considering the 'laws' regarding EMF and current distribution among components of RLC networks -- especially at resonance...

Impedance transformation is fundamental to electrical engineering (at least!)...

this

 

It process what is it ?

Start by considering the 'laws' regarding EMF and current distribution among components of RLC networks -- especially at resonance...