# Electronic Circuit Question.

#### Hypatia's Protege

Joined Mar 1, 2015
3,226
I understand this very well.
I hope so!

I am asking what to do with it now?
Apply it to the solution of the exercise in post #113

Again, impedance may be regarded as the EMF to current ratio --- Further to that, the 'clues' offered by @Aleph(0) and myself regarding the relationship of the transformation ratio to system 'Q' in this type of network should render the solution obvious!!!

System Quality Factor (Q) = √(transformation_ratio-1)
Q is proportion of reactance to resistance so like Qp=R/X and Qs=X/R

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#### RRITESH KAKKAR

Joined Jun 29, 2010
2,829
System Quality Factor (Q) = √(transformation_ratio-1)

Q is proportion of reactance to resistance so like Qp=R/X and Qs=X/R
What is the mean of quality factor here?
What is Qs and Qp ??
what it indicate?

#### RRITESH KAKKAR

Joined Jun 29, 2010
2,829

We will aplly DC or Sin wave AC?

#### Hypatia's Protege

Joined Mar 1, 2015
3,226
What is the mean of quality factor here?
Just as @Aleph(0) stated in the quoted text...

What is Qs and Qp
Qp = Q relevant to parallel connected reactor, resistor circuits.
Qs = Q relevant series connected reactor, resistor circuits.

what it indicate?
Apart from the relationship described in my previous post -- important implications of Q include bandwidth, efficiency, gain (in active systems), etc... -- but you needn't understand all of that at this point...

#### Hypatia's Protege

Joined Mar 1, 2015
3,226

We will aplly DC or Sin wave AC?
Inasmuch as I'm specifying a reactance what do you think?!

#### RRITESH KAKKAR

Joined Jun 29, 2010
2,829
Inasmuch as I'm specifying a reactance what do you think?!
it is AC because AC has reactance dc has resistance.

#### Hypatia's Protege

Joined Mar 1, 2015
3,226
it is AC because AC has reactance dc has resistance.
It's AC because inductors react to changing current and capacitors react to changing EMF

Resistance applies equally to AC and DC whereas reactance is possible only where the applied signal contains an 'alternating component'...

@RRITESH KAKKAR
Please note that the problem of post #113 is simplified by the fact that, inasmuch as reactance (as opposed to capacitance/inductance) is specified, you needn't concern yourself with frequency, waveform, etc...

#### RRITESH KAKKAR

Joined Jun 29, 2010
2,829
It's AC because inductors react to changing current and capacitors react to changing EMF
Ok that why Capacitor are rated in Voltage and inductor in henry.

#### Hypatia's Protege

Joined Mar 1, 2015
3,226
Ok that why Capacitor are rated in Voltage and inductor in henry.
The unit of capacitance is the Farad whereas the unit of inductance is the Henry --- E and I limits owe merely to reactor construction...

#### RRITESH KAKKAR

Joined Jun 29, 2010
2,829
ok,
i know this atleast.
What to do next?

#### Hypatia's Protege

Joined Mar 1, 2015
3,226
ok,
i know this atleast.
What to do next?
Again;
Apply it to the solution of the exercise in post #113

Again, impedance may be regarded as the EMF to current ratio --- Further to that, the 'clues' offered by @Aleph(0) and myself regarding the relationship of the transformation ratio to system 'Q' in this type of network should render the solution obvious!!!

#### RRITESH KAKKAR

Joined Jun 29, 2010
2,829

In this where is voltage source freq .
i think we will add Capacitor to absorb reactance from inductor.

#### RRITESH KAKKAR

Joined Jun 29, 2010
2,829
pls tell what to do next?
were is source and frequency.

#### Hypatia's Protege

Joined Mar 1, 2015
3,226
i think we will add Capacitor to absorb reactance from inductor.
Inasmuch as there are several ways of compensating the four ohms of inductive reactance, good practise will first design the transformation network without regard to port reactance - whereafter the most efficacious means of compensation will be evident...

So... The transformation ratio = 25/3 (i.e. 50/6) --- you take it from there!

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#### RRITESH KAKKAR

Joined Jun 29, 2010
2,829
So... The transformation ratio = 25/3 (i.e. 50/6) --- you take it from there!
OK, 25/3 = x/4
x=25*4/3=33.3ohm

#### Hypatia's Protege

Joined Mar 1, 2015
3,226
pls tell what to do next?
were is source and frequency.
Inasmuch as reactance is stipulated and sought frequency is irrelevent!

The assignment of 'source' and 'load' to the ports is unnecessary to the concept and solution of the exercise
-- That said; port #1 is consistent with a typical RF power BJT's collector impedance while port #2 is typical of a well matched antenna...

#### Hypatia's Protege

Joined Mar 1, 2015
3,226

#### RRITESH KAKKAR

Joined Jun 29, 2010
2,829
You tell what should be done?

#### RRITESH KAKKAR

Joined Jun 29, 2010
2,829

#### Hypatia's Protege

Joined Mar 1, 2015
3,226
You said take transformation ratio.
The transformation ratio is 25/3 -- but what's with the rest of your figures?