Electromagnet Turns And Same Field generated??

Thread Starter

russwr

Joined Aug 29, 2017
123
Original Source A about 12volts , 15 amps PULSING dc current , #16 gauge wire electromagnet 13 turns with steel core, for X amount of magnetic field. My source as only 4 amps available as PWM at 12 volts pulsing circuit . How many turns required in same LENGTH space to approx , same original required magnetic field? 0-4amps would then be variable capability field. Smaller Gauge wire also figured in for max 4 amps.
If windings are doubled, only 1/2 current required for same field.
 

ronsimpson

Joined Oct 7, 2019
4,645
You want the current to be 4/15. 4A not 15A
The turns need to be 49/13. 49 turns not 13 turns.
The Amps X Turns need to be about the same.
 

Loreani

Joined Mar 23, 2026
7
If you reduce the current from 15 A to 4 A, you’ll need proportionally more turns to get the same magnetic field in the same length. Basically, the magnetic field B∼N⋅IB \sim N \cdot IB∼N⋅I, so if you drop the current by about 4×, you’d need roughly 4× the turns. Using thinner wire works too, just make sure it can handle the current and fits in your coil length.
 

BobTPH

Joined Jun 5, 2013
11,463
Original Source A about 12volts , 15 amps PULSING dc current
With “pulsing” DC current into an inductor, the current will largely be determined by the frequency and duty cycle of the driving waveform with the inductance equation:

dI/dt = V/L.
 

MisterBill2

Joined Jan 23, 2018
27,159
What I don't think changes is THE POWER required to produce a given magnetic field strength. For any given constant source VOLTAGE, the current depends on the resistance, while the inductance ALSO places a limit on the rate of current increase at each pulse. Since we have no hint about the pulse rate there is no guess as to the actual average current, and since the inductance will be different with a different number of turns, there is another unknown.
 
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