Hi guys, I've been reading through these books and have been learning and understanding everything up to the clamper circuit section in the diodes chapter in the semiconductor book.
http://www.allaboutcircuits.com/vol_3/chpt_3/7.html
Some of the information doesn't add up in my mind, so I wanted to ask you generous guys and gals for some clarification.
There's this sentence:
"On the first positive half cycle, the diode conducts charging the capacator left end to +5 V."
I get that. The capacitor charges and has a ~5v drop across its two terminals. The left is +5 to ground and the right terminal is 0v to ground.
But then the next few sentences make my brain explode:
"This is -5v on the right end... The right end of the capacator is at -5v DC with respect to ground."
I cannot understand this. Isn't the right end of the cap at ground in the first half cycle? Isn't it more likely that the right end is -5v DC with respect to node 4 - not ground?
http://www.allaboutcircuits.com/vol_3/chpt_3/7.html
Some of the information doesn't add up in my mind, so I wanted to ask you generous guys and gals for some clarification.
There's this sentence:
"On the first positive half cycle, the diode conducts charging the capacator left end to +5 V."
I get that. The capacitor charges and has a ~5v drop across its two terminals. The left is +5 to ground and the right terminal is 0v to ground.
But then the next few sentences make my brain explode:
"This is -5v on the right end... The right end of the capacator is at -5v DC with respect to ground."
I cannot understand this. Isn't the right end of the cap at ground in the first half cycle? Isn't it more likely that the right end is -5v DC with respect to node 4 - not ground?