Does 25 Amps really require a trace width of 26 Millimeters?

Thread Starter

Morad Tamer

Joined Oct 21, 2016
34
The first reasonable compromise is to accept 30°C temperature rise in the track. The second, which is often not an option with low-cost fast-turn prototype board houses is to use 2 ounce (0.0028", 0.07 mm) copper. Even 4 ounce copper begins to impose limitations on trace & space width. Anything over four ounce is going to cost substantially more because it ties up the board fab's plating line for a long long time.

Again, a 4N25 has a specified current transfer ratio (CTR) of nominally 0.2. That means for each mA through the input emitter, you can expect only 200 µA through the transistor. For 77 mA for the relay, you would have to put 385 milliamps - over a third of an ampere - through the input emitter. It would be instantly destroyed.
Thank you very much
 

panic mode

Joined Oct 10, 2011
2,761
R2 and R3 are to make a voltage divider to achieve the Opto-Couplers operating voltage
U1 is the Opto-Coupler itself
i assure you that i know that those are resistors and optocouplers.
my question was what is the purpose of R2,R3 and U1 in THIS circuit?

there is no need for any of them...
 

olphart

Joined Sep 22, 2012
114
I prefer standard 12 or 14 AWG solid wire to beef up a power trace.
Got scraps from house wiring projects.
I use a Weller 100/150W gun, since it does take some wattage.
 
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