In this article:
http://en.wikipedia.org/wiki/Diode_modelling
where it says about the Ideal diode in series with voltage source.
What if I apply 1V to the anode of the ideal diode, and 5V to the "minus" of the voltage source? So I have a potential difference of -4V over the Ideal diode in series with voltage source.
Then because the anode of the ideal diode is at 1V and the cathode at 0.7V, then the ideal diode has a potential difference over it of 0.3V. Thus the ideal diode is short circuit.
Thus the Ideal diode in series with voltage source is a short circuit+voltage source. But the potential difference over it is -4V. It should be a short circuit+voltage source only if the potential difference over it is greater than 0.7V.
Or I could say. What if I apply 0V to the anode and -2V to the minus. So I have a +2V over the Ideal diode in series with voltage source. This is greater than 0.7V => it should conduct. But the voltage over the ideal diode is 0-0.7V <0V. Thus the ideal diode is open circuit.
???
Am I saying something wrong? I am confused.
PS: for me Vt = 0.7V
http://en.wikipedia.org/wiki/Diode_modelling
where it says about the Ideal diode in series with voltage source.
What if I apply 1V to the anode of the ideal diode, and 5V to the "minus" of the voltage source? So I have a potential difference of -4V over the Ideal diode in series with voltage source.
Then because the anode of the ideal diode is at 1V and the cathode at 0.7V, then the ideal diode has a potential difference over it of 0.3V. Thus the ideal diode is short circuit.
Thus the Ideal diode in series with voltage source is a short circuit+voltage source. But the potential difference over it is -4V. It should be a short circuit+voltage source only if the potential difference over it is greater than 0.7V.
Or I could say. What if I apply 0V to the anode and -2V to the minus. So I have a +2V over the Ideal diode in series with voltage source. This is greater than 0.7V => it should conduct. But the voltage over the ideal diode is 0-0.7V <0V. Thus the ideal diode is open circuit.
???
Am I saying something wrong? I am confused.
PS: for me Vt = 0.7V
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