In this case, when the diode become OPEN CIRCUIT. And the Vdiode measured will be 5V which is actually measuring the Vdc or the Vsource. But basically the diode is burnt , so … no diode -no voltage- This statement is correct?


It would actually depend upon where the probes were placed. If placed below the opening in the circuit, you would see 0V. but if probed above the break, you would see full source voltage. I think we are getting confused by a bad component vs a bad wire. Both are possible failure modes.

 

Thanks BillB3857 .