I have to design the amplification circuit, so I cannot use the HX711hi MMM,
I have one of those, the elements are 1K each, use 5Vdc and it outputs 1mV/Volt.
So full scale 1kG gives 5mV.
They work well with the HX711 load cell amplifier and data output.
What are you driving with the INA amplifier output voltage.?
E
The full scale 1 KG gives 5.3 mV in my case instead of 5mVhi MMM,
I have one of those, the elements are 1K each, use 5Vdc and it outputs 1mV/Volt.
So full scale 1kG gives 5mV.
They work well with the HX711 load cell amplifier and data output.
What are you driving with the INA amplifier output voltage.?
E
Ok, I willhi,
Try post #63
E
What V4 represents?hi MMM,
Please try this battery connection with your circuit +4.5 and -1.5V
Using your TL082 OPA's
V3 is a test 5mVolt voltage for the output of the load cell at 1kG load
Let us know what you see
E
R9,10,11,12 are the resistive elements of your load cell bridge
View attachment 282520
ANY change in a signal involves an AC component. In your case, any time the weight changes, the signal changes. The faster you want your system to respond to that change, the higher the frequency that the components of that signal change have.Ok, I am working on a weight sensor, this sensor only gives a DC (using oscilloscope to view the signal, it was very close to a DC as long as the input is the same, when a change occurs in the input, the DC level will change but it is still DC). I just want to mention that there is no AC source, capacitors, or inductors, Thus, I think it is totally DC.
Again, many thanks for your contribution, this opens a new door for me to look for other ways
This makes this whole thing sound like a college assignment of some kind. Is it?I have to design the amplification circuit, so I cannot use the HX711
hi MM,The full scale 1 KG gives 5.3 mV in my case instead of 5mV
What do you mean that you don't know the model of that weight sensor? It's right in the Amazon listing. It's a uxcell model YZC-131.https://www.amazon.com/Uxcell-a14071900ux0078-Aluminum-Weighting-Sensor/dp/B00QC6M45A/ref=sr_1_4?crid=25F7VSTFIE9H4&keywords=load+cell+1kg&qid=1670492562&sprefix=load+cell+1k,aps,201&sr=8-4
The specs are written in the description of the product. I could not find its datasheet because I don't know the model of that weight sensor
hi MMM,
Please try this battery connection with your circuit +4.5 and -1.5V
Using your TL082 OPA's
V3 is a test 5mVolt voltage for the output of the load cell at 1kG load
Let us know what you see
E
R9,10,11,12 are the resistive elements of your load cell bridge
View attachment 282520
What are you driving with the INA amplifier output voltage?Hi
Connect the R8 to 0v.
The V4 was used to check an offset, not used on your project.
>
What are you driving with the INA amplifier output voltage.?
E
@MMM**MMM
Connect your Load Cell as test voltage source
Note: V3 represents the voltage output of the load cell when it has a weight of1kG on it.
The Gain is set by R3 50 Ohms. to Gain= 400
I am still confused, how does a weight sensor involve an AC component? The output is just due to the variations in resistances due to the deviation of the beam itself. So, there is no AC component, this is what I understand, please correct me if I am wrong.ANY change in a signal involves an AC component. In your case, any time the weight changes, the signal changes. The faster you want your system to respond to that change, the higher the frequency that the components of that signal change have.
How long after a change in the weight do you need the output signal of your amplifier to have stabilized at the new value? If it's a few seconds, then you only need a very low bandwidth of a few hertz. If you need it to respond in a few milliseconds, then you need several kilohertz of bandwidth.
V5 should be the +4.5V and V9 should be the 1.5V supplies. You have them connected wrong!View attachment 282569
I think this is very similar to your circuit, still cannot get the output we need. What about the AD623AN and the multistage amplifier? I don't mind using both of them
No. A TL082 uses P-channel Jfets in its inputs and some of them Do Not Work if the input voltage is within 4V from the negative supply. It is recommended in Texas Instruments latest update to have a minimum supply that is +5V/-5V.V5 should be the +4.5V and V9 should be the 1.5V supplies. You have them connected wrong!
Ah, I see now what you're doing, my apologies.No. A TL082 uses P-channel Jfets in its inputs and some of them Do Not Work if the input voltage is within 4V from the negative supply. It is recommended in Texas Instruments latest update to have a minimum supply that is +5V/-5V.
Any signal can be represented as the superposition of a spectrum of sinusoidal waveforms of different amplitudes and frequencies from zero hertz to infinite hertz. The only way for there to be NO energy at ANY frequency other than 0 Hz (also known as "DC") is if the signal has existed since the beginning of time, has never changed, and will never change until the end of time. ANY signal that has ever or will ever undergo any change, has non-zero content at non-zero frequencies.I am still confused, how does a weight sensor involve an AC component? The output is just due to the variations in resistances due to the deviation of the beam itself. So, there is no AC component, this is what I understand, please correct me if I am wrong.
"How long after a change in the weight do you need the output signal of your amplifier to have stabilized at the new value?" It doesn't matter, one second is fine, I don't need a very very high response.
.V5 should be the +4.5V and V9 should be the 1.5V supplies. You have them connected wrong!