I have seen this exact question posted before but was not able to figure it out still, i need to create an LED in digital works 95 that shows 16 followed by my student number. I have created a truth table and Boolean equations but i do not know how to create the circuit, any help would be great. Thanks

problem:
Design a circuit to take a binary input and display a number on the counter. The counter needs to display the number 1 followed by 6 to indicate the year the coursework was done (i.e. 2016). Then this will be followed by your unique student ID number (person number). This will mean that everybody will have a unique problem to solve as no two students have the same student number. So if your student number was 123456 then your counter would need to display 16123456.

Build a circuit using only AND, OR, NOT, NAND and NOR logic gates to simulate the counter. You should use 3 sequencers or bit generators in your circuit as input. Draw your circuit using Digital Works 95. The numbers should change automatically without any user input. HINT: First construct a separate circuit for each segment from the truth table you have constructed. Then redraw the circuit to combine the separate circuits to form one complete circuit.

 

This was discussed here.

 

Yeah, i saw that post but it didn't really help me as i have no idea what i am doing.

 

Welcome to AAC!

Yeah, i saw that post but it didn't really help me as i have no idea what i am doing.

Post what you've done so far.

Is you student number octal? If you have any 8 or 9 digits, you need 4 sequencers.

This problem was also mentioned in this thread. The OP said he figured out the main part of the problem, but didn't post a schematic...

 

The number is 16 767896
it says in the problem above that i can only use 3 sequences.
I have uploaded everything that i have done so far, i am struggling to create the outputs on the circuit as i am unsure how i change the equations into logic gates.

 

In your truth table, you only go up to 7. How can you represent 8 or 9 with only 3 sequencers? That limit must be an error in the problem statement, or it was written for a case where student numbers were octal and wasn't modified appropriately.

What are you trying to show with the truth table columns for NOT and AND gates?

When the count is zero, which segments on the display should be on? Which are you indicating to be on?