Consider your first transformation below:



It is usually helpful to label nodes in both circuits and sanity check that the work makes sense. In the left diagram Nodes A and B are quite distinct, but in the circuit at the right you have them shorted together.

Also note that those horizontal 20 Ω resistors in the left diagram are connected directly to the very top node, but that you haven't preserved this relationship in your transformed circuit, but you have connected the 80/3 Ω resistors directly to the top node when that is not how they are connected in the original circuit.

The bottom line is that you've actually made quite a hash of this transformation. Sorry I didn't look more closely the first time around.

One trick that you can use on a circuit like this is to take the top resistor and split it into two resistors that are twice the size but are in parallel. The you can use one of them for the left half and one for the right half.

 

so my answer wasn't right?

 

sorry i was so busy with other projects.

 

so my answer wasn't right?

That correct -- you're answer was not right. But it worked out, by coincidence only, to an answer that is numerically very close to the correct answer and thus pretty easy to miss the error.