hello friends,
In the current mirror arrangement our idea is to make the collector current in the second transistor equal to reference current in the first transistor, ie
I ref = Ic+Ib
in the first transistor, now we try to make Ib as small as posssible so that I ref is approximately equal to Ic which is the current in the collector of the second transistor as well.
my question is why do we short the collector and base of the first transistor, if we don't short I ref=Ic and we don't have Ib coming into the picture.
Sorry if the question is too simple or silly, I have just started learning.
In the current mirror arrangement our idea is to make the collector current in the second transistor equal to reference current in the first transistor, ie
I ref = Ic+Ib
in the first transistor, now we try to make Ib as small as posssible so that I ref is approximately equal to Ic which is the current in the collector of the second transistor as well.
my question is why do we short the collector and base of the first transistor, if we don't short I ref=Ic and we don't have Ib coming into the picture.
Sorry if the question is too simple or silly, I have just started learning.